X^2+40(x2)=1080

Solution for X^2+40(x2)=1080 equation:

X^2+40(X2)=1080

We move all terms to the left:

X^2+40(X2)-(1080)=0

We add all the numbers together, and all the variables

41X^2-1080=0

a = 41; b = 0; c = -1080;
Δ = b2-4ac
Δ = 02-4·41·(-1080)
Δ = 177120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{177120}=\sqrt{144*1230}=\sqrt{144}*\sqrt{1230}=12\sqrt{1230}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{1230}}{2*41}=\frac{0-12\sqrt{1230}}{82}
=-\frac{12\sqrt{1230}}{82}
=-\frac{6\sqrt{1230}}{41}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{1230}}{2*41}=\frac{0+12\sqrt{1230}}{82}
=\frac{12\sqrt{1230}}{82}
=\frac{6\sqrt{1230}}{41}
$